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What Resistance Will Lead to The Best Flavor?

Launch Time: 2016-11-15 Views: 1254 Rely: 0 Started by:

 


With the progress of the times, innovation and production of the pressure regulating devices of the ecigs have been obtained a lot while the taste has more and more become a bewildering thing. The flavor is determined by a number of factors such as the atomizer structure, the coil data and the output wattage, etc,along with the different tastes of each person, vapers are constantly making coils to adjust the output wattage in looking for a better taste, which of course, is one of the joy of vaping

 

But many novices will be surrounded with doubts and the commonly doubt is: what resistance will lead to the best flavor under the VW mode? Many of our fans have make tests to figure out more possibilities and here, Ceci from Cacuq will tell you some ways to find out the most suitable resistance providing the best flavor.

 

If we want to get further analysis of a problem, we must first get know of the principle of the occurrence of this item. The basic principle of electronic cigarette is a simple circuit, which just means the battery providing power for the device with current and the coil in the atomizer is the source of resistance. The principle of electronic cigarettes is to use the power to make the wire to produce effect of heat so as to have the double sides of cotton evaporated to become of water vapor, resulting in the vapor.

 

 

 

Electronic cigarettes use the battery as the power supply to produce voltage. The commonly used voltage of the ecigs are 3.7V while when the battery is fully charged, the highest voltage will be around 4.2V. With the increase of the working time, the voltage will be consumed and thus decreasing gradually. So we can find our most suitable favor during the bearing range of the voltages. So we have to understand some of the common electrical variables involved in the electronic cigarette: voltage (U), current (I), resistance (R), power (W).

 

Ceci will share a way to figure out your most suitable flavor by accurate specifications.

Calculating method


This kind of way starts from the mechanical mods period and at the previous time, there are no protection mechanism and tips of specifications on the mod so in order to properly and safely use the mod, they should physically calculate the proper voltage specifications.If we know the wire resistance and the voltage, we can calculate the suitable power:power = voltage square divide resistance.(W=U²/R)

For example, what watt is the most suitable to pull out the 0.2Ω resistance? what watt is the most suitable to pull out the 0.5Ω resistance? what watt is the most suitable to pull out the 0.9Ω resistance?
Normally, the standard of the voltage of the mod is during 3.7V-4.2V and using the formula, you will get that 0.2Ω suitable power is 68W-88W and the 0.5Ω suits with 27-35W and the last 0.9Ω is 15-19.6W.